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Popular >

y^'+2x^2y=0

Solution

y^{^{'}} + 2 x^{2} y = 0

Solution

y = e^{- \frac{2 x ^{3}}{3} + c_{1}}

Solution steps

y^{'} (x) + 2 x^{2} y = 0

Solve separable ODE:

y = e^{- \frac{2 x ^{3}}{3} + c_{1}}

y = e^{- \frac{2 x ^{3}}{3} + c_{1}}

Popular Examples

(dy)/(dx)=(3x^2+4x+2)/(2y+1),y(0)=-1

\frac{d y}{d x} = \frac{3 x ^{2} + 4 x + 2}{2 y + 1}, y (0) = - 1

(dv)/(dt)=30-9/100 v,v=0,t=0

\frac{d v}{d t} = 30 - \frac{9}{100} v, v = 0, t = 0

(2y+2)dy-(4x^3+6)dx=0

(2 y + 2) d y - (4 x^{3} + 6) d x = 0

(2+y)dx-(x-1)dy=0

(2 + y) d x - (x - 1) d y = 0

\frac{y ^{^{'}}}{x} = y

Frequently Asked Questions (FAQ)

What is the solution for y^'+2x^2y=0 ?
The solution for y^'+2x^2y=0 is y=e^{-(2x^3)/3+c_{1}}