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Popular >

y^'=(2-y)t

Solution

y^{^{'}} = (2 - y) t

Solution

y = - e^{- \frac{t ^{2}}{2} - c_{1}} + 2

Solution steps

y^{'} (t) = (2 - y) t

Solve separable ODE:

y = - e^{- \frac{t ^{2}}{2} - c_{1}} + 2

y = - e^{- \frac{t ^{2}}{2} - c_{1}} + 2

Popular Examples

(x-x^2)y^'=2y,y(2)=4

(x - x^{2}) y^{^{'}} = 2 y, y (2) = 4

(dy)/(dx)=(y+1)*(x+1)*cos(x^2+2x)

\frac{d y}{d x} = (y + 1) \cdot (x + 1) \cdot cos (x^{2} + 2 x)

y^'=9*t*e^{-y},y(0)=3

y^{^{'}} = 9 \cdot t \cdot e^{- y}, y (0) = 3

y^'=csc(y)cos(x/2),y(3pi)=(3pi)/2

y^{^{'}} = csc (y) cos (\frac{x}{2}), y (3 π) = \frac{3 π}{2}

(dy)/(dx)tan(y)=x

\frac{d y}{d x} tan (y) = x

Frequently Asked Questions (FAQ)

What is the solution for y^'=(2-y)t ?
The solution for y^'=(2-y)t is y=-e^{-(t^2)/2-c_{1}}+2