What is the solution for y^'=-0.06sqrt(y) ?

The solution for y^'=-0.06sqrt(y) is y=(9t^2}{10000}-(3c_{1}t)/(100)+\frac{c_{1}^2)/4

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y^'=-0.06sqrt(y)

y^{^{'}} = - 0.06 y

y = \frac{9 t ^{2}}{10000} - \frac{3 c _{1} t}{100} + \frac{c _{1}^{2}}{4}

Solution steps

y^{'} (t) = - 0.06 y

Solve separable ODE:

y = \frac{9 t ^{2}}{10000} - \frac{3 c _{1} t}{100} + \frac{c _{1}^{2}}{4}

y = \frac{9 t ^{2}}{10000} - \frac{3 c _{1} t}{100} + \frac{c _{1}^{2}}{4}

\frac{d y}{d x} = \frac{x ^{2} - 1}{y ^{2} - 1}, y (2) = 2

y^{^{'}} = 7 y, y (0) = 1

f (x) = x^{5} cos (x) f^{^{'}} (x)

q^{^{'}} + \frac{1}{50} q = 0.2, q (0) = 5

sin (x) sin (y) y^{^{'}} + cos (y) cos (x) = 0

What is the solution for y^'=-0.06sqrt(y) ?
The solution for y^'=-0.06sqrt(y) is y=(9t^2}{10000}-(3c_{1}t)/(100)+\frac{c_{1}^2)/4