What is the solution for 3t^5(dx)/(dt)+6x-5=0 ?

The solution for 3t^5(dx)/(dt)+6x-5=0 is x=(e^{(1-12c_{1}t^4)/(2t^4)})/6+5/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3t^5(dx)/(dt)+6x-5=0

3 t^{5} \frac{d x}{d t} + 6 x - 5 = 0

x = \frac{e ^{\frac{1 - 12 c _{1} t ^{4}}{2 t ^{4}}}}{6} + \frac{5}{6}

Solution steps

3 t^{5} \frac{d x}{d t} + 6 x - 5 = 0

Solve separable ODE:

x = \frac{e ^{\frac{1 - 12 c _{1} t ^{4}}{2 t ^{4}}}}{6} + \frac{5}{6}

x = \frac{e ^{\frac{1 - 12 c _{1} t ^{4}}{2 t ^{4}}}}{6} + \frac{5}{6}

\frac{d y}{d x} = 3 - 0.04 y

\frac{d y}{d x} = \frac{y cos ( x )}{1 + y ^{2}}, y (0) = 1

\frac{d}{d θ} (y (θ)) + y (θ) = 0

y^{^{'}} = - 3 y, y (0) = e^{- 3 t}, y (0) = 1

\frac{d y}{d x} + ln (x) y = 3 ln (x)

What is the solution for 3t^5(dx)/(dt)+6x-5=0 ?
The solution for 3t^5(dx)/(dt)+6x-5=0 is x=(e^{(1-12c_{1}t^4)/(2t^4)})/6+5/6