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Popular >

(dx)/(dy)+2xy^2=0

Solution

\frac{d x}{d y} + 2 x y^{2} = 0

Solution

x = e^{- \frac{2 y ^{3}}{3} + c_{1}}

Solution steps

\frac{d x}{d y} + 2 x y^{2} = 0

Solve separable ODE:

x = e^{- \frac{2 y ^{3}}{3} + c_{1}}

x = e^{- \frac{2 y ^{3}}{3} + c_{1}}

Popular Examples

(x^2+1)(dy)/(dx)+3x(y-1)=0,y(0)=5

(x^{2} + 1) \frac{d y}{d x} + 3 x (y - 1) = 0, y (0) = 5

(x^3+1)y^'=x^2y

(x^{3} + 1) y^{^{'}} = x^{2} y

y^2(x+1)+2xyy^'=0

y^{2} (x + 1) + 2 x y y^{^{'}} = 0

(t^2-16t+55)*(dy)/(dt)=y

(t^{2} - 16 t + 55) \cdot \frac{d y}{d t} = y

(dy)/(dx)=e^{-x-y-2}

\frac{d y}{d x} = e^{- x - y - 2}

Frequently Asked Questions (FAQ)

What is the solution for (dx)/(dy)+2xy^2=0 ?
The solution for (dx)/(dy)+2xy^2=0 is x=e^{-(2y^3)/3+c_{1}}