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Popular >

y^'=yln(x)

Solution

y^{^{'}} = y ln (x)

Solution

y = e^{- x + c_{1}} x^{x}

Solution steps

y^{'} (x) = y ln (x)

Solve separable ODE:

y = e^{- x + c_{1}} x^{x}

y = e^{- x + c_{1}} x^{x}

Graph

Popular Examples

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tan (x) sin^{2} (y) d x + cos^{2} (x) cos (y) d y = 0

Frequently Asked Questions (FAQ)

What is the solution for y^'=yln(x) ?
The solution for y^'=yln(x) is y=e^{-x+c_{1}}x^x