What is the solution for 3(dy)/(dx)-7(dy)/(dx)+3y=0 ?

The solution for 3(dy)/(dx)-7(dy)/(dx)+3y=0 is y=e^{(3x+c_{1})/4}

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3(dy)/(dx)-7(dy)/(dx)+3y=0

3 \frac{d y}{d x} - 7 \frac{d y}{d x} + 3 y = 0

y = e^{\frac{3 x + c _{1}}{4}}

Solution steps

3 \frac{d y}{d x} - 7 \frac{d y}{d x} + 3 y = 0

Solve separable ODE:

y = e^{\frac{3 x + c _{1}}{4}}

y = e^{\frac{3 x + c _{1}}{4}}

\frac{d y}{d x} = \frac{x}{y ^{2}}, y (2) = 3

(2 - x^{3}) y^{^{'}} - 3 x^{2} y = 0

\frac{d y}{d x} = (\frac{y}{x})

u^{^{'}} = 2 e^{7 x - H (x)}

2 (x^{2} y - y) d y - (2 x y^{2} - 2 x) d x = 0

What is the solution for 3(dy)/(dx)-7(dy)/(dx)+3y=0 ?
The solution for 3(dy)/(dx)-7(dy)/(dx)+3y=0 is y=e^{(3x+c_{1})/4}