What is the solution for y^'-(xsin(x))/(3y^2)=0,y(0)=2 ?

The solution for y^'-(xsin(x))/(3y^2)=0,y(0)=2 is y=\sqrt[3]{-xcos(x)+sin(x)+8}

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y^'-(xsin(x))/(3y^2)=0,y(0)=2

y^{^{'}} - \frac{x sin ( x )}{3 y ^{2}} = 0, y (0) = 2

Solution steps

y^{'} (x) - \frac{x sin ( x )}{3 y ^{2}} = 0

Solve separable ODE:

u^{^{'}} = e^{4 x - H (x)}

\frac{d y}{d x} + 2 x y = 2 x, y (0) = 2

\frac{d y}{d x} + 5 y = 20, y (0) = 2

\frac{d y}{d x} = \frac{- x + x y ^{2}}{y + x ^{2} y}

y^{^{'}} = x^{2} - 2 x^{2} y

What is the solution for y^'-(xsin(x))/(3y^2)=0,y(0)=2 ?
The solution for y^'-(xsin(x))/(3y^2)=0,y(0)=2 is y=\sqrt[3]{-xcos(x)+sin(x)+8}