What is the solution for (dx)/(dt)=0.36-(9x)/(100) ?

The solution for (dx)/(dt)=0.36-(9x)/(100) is x=-e^{(-9t-c_{1})/(100)}+4

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(dx)/(dt)=0.36-(9x)/(100)

\frac{d x}{d t} = 0.36 - \frac{9 x}{100}

x = - e^{\frac{- 9 t - c _{1}}{100}} + 4

Solution steps

\frac{d x}{d t} = 0.36 - \frac{9 x}{100}

Solve separable ODE:

x = - e^{\frac{- 9 t - c _{1}}{100}} + 4

x = - e^{\frac{- 9 t - c _{1}}{100}} + 4

u^{^{'}} = x^{2} H (x)

\frac{d y}{d x} = - \frac{3 x + 3 x y ^{2}}{y x ^{2} + 2 y}

\frac{( d y )}{( d x )} = (2 x + 10) \cdot e^{- y}, y (0) = 0

g = \frac{d v}{d t} + v^{2} k

y^{^{'}} - 2 y = 2 y^{\frac{1}{2}}

What is the solution for (dx)/(dt)=0.36-(9x)/(100) ?
The solution for (dx)/(dt)=0.36-(9x)/(100) is x=-e^{(-9t-c_{1})/(100)}+4