What is the solution for (dr)/(dt)=0.1872r,r(0)=24 ?

The solution for (dr)/(dt)=0.1872r,r(0)=24 is r=24e^{0.1872t}

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(dr)/(dt)=0.1872r,r(0)=24

\frac{d r}{d t} = 0.1872 r, r (0) = 24

r = 24 e^{0.1872 t}

Solution steps

\frac{d r}{d t} = 0.1872 r

Solve separable ODE:

r = 24 e^{0.1872 t}

r = 24 e^{0.1872 t}

y^{^{'}} + 2 x y^{2} = 0, y (0) = \frac{1}{x ^{2} + c}, y (0) = 1

(x - y x) d y + y d x = 0

\frac{( d y )}{( d x )} = e^{(3 y - x)}

\frac{d y}{d t} - 0.5 y + 2 = 0

2 y^{^{'}} = 3 y^{\frac{1}{3}}

What is the solution for (dr)/(dt)=0.1872r,r(0)=24 ?
The solution for (dr)/(dt)=0.1872r,r(0)=24 is r=24e^{0.1872t}