en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dt)-0.5y+2=0

Solution

\frac{d y}{d t} - 0.5 y + 2 = 0

Solution

y = 2 e^{\frac{t + c _{1}}{2}} + 4

Solution steps

\frac{d y}{d t} - 0.5 y + 2 = 0

Solve separable ODE:

y = 2 e^{\frac{t + c _{1}}{2}} + 4

y = 2 e^{\frac{t + c _{1}}{2}} + 4

Popular Examples

2 y^{^{'}} = 3 y^{\frac{1}{3}}

y-yy^'+2y=cos(8)

y - y y^{^{'}} + 2 y = cos (8)

(t^2-24t+95)y^'=y

(t^{2} - 24 t + 95) y^{^{'}} = y

derivative of x^4+y^4= derivative of 16

\frac{d}{d x} (x^{4} + y^{4}) = \frac{d}{d x} (16)

(x^2-1)(dy)/(dx)=y^2-1,y(2)=2

(x^{2} - 1) \frac{d y}{d x} = y^{2} - 1, y (2) = 2

Frequently Asked Questions (FAQ)

What is the solution for (dy)/(dt)-0.5y+2=0 ?
The solution for (dy)/(dt)-0.5y+2=0 is y=2e^{(t+c_{1})/2}+4