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Popular >

5dx-e^{y-x}dy=0

Solution

5 d x - e^{y - x} d y = 0

Solution

y = ln (5 e^{x} + c_{1})

Solution steps

5 d x - e^{y - x} d y = 0

Solve separable ODE:

y = ln (5 e^{x} + c_{1})

y = ln (5 e^{x} + c_{1})

Popular Examples

(dy)/(dx)=3x^2y,y=9,x=0

\frac{d y}{d x} = 3 x^{2} y, y = 9, x = 0

(dy)/(dx)=3y+2,y(0)=1

\frac{d y}{d x} = 3 y + 2, y (0) = 1

y^{^{'}} = 5 y, y (0) = 10

(dy)/(dx)=((3x^2+4x+2)/(2(y-1)))

\frac{d y}{d x} = (\frac{3 x ^{2} + 4 x + 2}{2 ( y - 1 )})

y(dy)/(dx)=5x(y^2+5)^2

y \frac{d y}{d x} = 5 x (y^{2} + 5)^{2}

Frequently Asked Questions (FAQ)

What is the solution for 5dx-e^{y-x}dy=0 ?
The solution for 5dx-e^{y-x}dy=0 is y=ln(5e^x+c_{1})