What is the solution for (dy)/(dx)=((y-1)/(x+3)) ?

The solution for (dy)/(dx)=((y-1)/(x+3)) is y=e^{c_{1}}x+3e^{c_{1}}+1

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(dy)/(dx)=((y-1)/(x+3))

\frac{d y}{d x} = (\frac{y - 1}{x + 3})

y = e^{c_{1}} x + 3 e^{c_{1}} + 1

Solution steps

\frac{d y}{d x} = (\frac{y - 1}{x + 3})

Solve separable ODE:

y = e^{c_{1}} x + 3 e^{c_{1}} + 1

y = e^{c_{1}} x + 3 e^{c_{1}} + 1

\frac{d y}{d x} + 2 x y - x = 0

(1 + x) \frac{d y}{d x} + y = 2 e^{2 π}

y = e^{c o s (x^{2})} y^{^{'}}

y (1 - x^{2}) d y - x (1 - y^{2}) d x = 0

y^{^{'}} = \frac{t y ^{2}}{t ^{2} + e}

What is the solution for (dy)/(dx)=((y-1)/(x+3)) ?
The solution for (dy)/(dx)=((y-1)/(x+3)) is y=e^{c_{1}}x+3e^{c_{1}}+1