What is the solution for y=e^{cos(x^2)}y^' ?

The solution for y=e^{cos(x^2)}y^' is y=e^{integral of 1/(e^{cos(x^2))}}

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y=e^{cos(x^2)}y^'

y = e^{c o s (x^{2})} y^{^{'}}

y = e^{\int \frac{1}{e ^{c o s (x^{2})}} d x}

Solution steps

y = e^{c o s (x^{2})} y^{'} (x)

Solve separable ODE:

y = e^{\int \frac{1}{e ^{c o s (x^{2})}} d x}

y = e^{\int \frac{1}{e ^{c o s (x^{2})}} d x}

y (1 - x^{2}) d y - x (1 - y^{2}) d x = 0

y^{^{'}} = \frac{t y ^{2}}{t ^{2} + e}

y^{^{'}} = 1 + y + y^{2}

\frac{d y}{d x} = \frac{x ^{3}}{2 y ^{2}}

\frac{d y}{d x} = - \frac{0.1}{cos ( y )}, y (0) = \frac{π}{2}

What is the solution for y=e^{cos(x^2)}y^' ?
The solution for y=e^{cos(x^2)}y^' is y=e^{integral of 1/(e^{cos(x^2))}}