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Popular >

y^'=6xsqrt(4-y^2)

Solution

y^{^{'}} = 6 x 4 - y^{2}

Solution

y = 2 sin (3 x^{2} + c_{1})

Solution steps

y^{'} (x) = 6 x 4 - y^{2}

Solve separable ODE:

y = 2 sin (3 x^{2} + c_{1})

y = 2 sin (3 x^{2} + c_{1})

Popular Examples

y^{^{'}} = y^{2} + 2

(dy)/(dx)=-4/4 x^8y^4

\frac{d y}{d x} = - \frac{4}{4} x^{8} y^{4}

(dy)/(dt)+2(t+1)y^2=0,y(0)=-1/8

\frac{d y}{d t} + 2 (t + 1) y^{2} = 0, y (0) = - \frac{1}{8}

y^'=(ln(x))/(xy),y(1)=2

y^{^{'}} = \frac{ln ( x )}{x y}, y (1) = 2

-((dx)/(dy))=((x^2y^2))/((1+x))

- (\frac{d x}{d y}) = \frac{( x ^{2} y ^{2} )}{( 1 + x )}

Frequently Asked Questions (FAQ)

What is the solution for y^'=6xsqrt(4-y^2) ?
The solution for y^'=6xsqrt(4-y^2) is y=2sin(3x^2+c_{1})