What is the derivative of x^2+3x+5 ?

The derivative of x^2+3x+5 is 2x+3

What is the first derivative of x^2+3x+5 ?

The first derivative of x^2+3x+5 is 2x+3

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\frac{d}{d x} (x^{2} + 3 x + 5)

2 x + 3

Solution steps

\frac{d}{d x} (x^{2} + 3 x + 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (3 x) + \frac{d}{d x} (5)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (5) = 0

= 2 x + 3 + 0

Simplify

= 2 x + 3

x \to 2 lim (\frac{4}{( x - 2 ) ^{3}})

\frac{d}{d x} (d cos (x) + x^{2} sin (x))

n = 1 \sum \infty \frac{3}{n ^{\frac{5}{3}}}

∣ x ∣ + 3

f (x) = sec (x), (\frac{π}{3}, 2)

What is the derivative of x^2+3x+5 ?
The derivative of x^2+3x+5 is 2x+3
What is the first derivative of x^2+3x+5 ?
The first derivative of x^2+3x+5 is 2x+3