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Popular >

y^'=xy-2x,y(0)=3

Solution

y^{^{'}} = x y - 2 x, y (0) = 3

Solution

y = e^{\frac{x ^{2}}{2}} + 2

Solution steps

y^{'} (x) = x y - 2 x

Solve separable ODE:

y = e^{\frac{x ^{2}}{2}} + 2

y = e^{\frac{x ^{2}}{2}} + 2

Popular Examples

(dy)/(dt)=(9t^2)/(8y)

\frac{d y}{d t} = \frac{9 t ^{2}}{8 y}

cos(y)dy=sin(x)dx

cos (y) d y = sin (x) d x

(dy)/(dx)=(4x)/(3y+1)

\frac{d y}{d x} = \frac{4 x}{3 y + 1}

x(dy)/(dx)-(1-x^2)y=0

x \frac{d y}{d x} - (1 - x^{2}) y = 0

y^'=xy^{1/2},y(0)= 1/16 x^4

y^{^{'}} = x y^{\frac{1}{2}}, y (0) = \frac{1}{16} x^{4}

Frequently Asked Questions (FAQ)

What is the solution for y^'=xy-2x,y(0)=3 ?
The solution for y^'=xy-2x,y(0)=3 is y=e^{(x^2)/2}+2