What is the solution for cos(y)dy=sin(x)dx ?

The solution for cos(y)dy=sin(x)dx is y=arcsin(-cos(x)+c_{1})+2pin,y=pi+arcsin(cos(x)-c_{1})+2pin

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cos(y)dy=sin(x)dx

cos (y) d y = sin (x) d x

y = arcsin (- cos (x) + c_{1}) + 2 πn, y = π + arcsin (cos (x) - c_{1}) + 2 πn

Solution steps

cos (y) d y = sin (x) d x

Solve separable ODE:

y = arcsin (- cos (x) + c_{1}) + 2 πn, y = π + arcsin (cos (x) - c_{1}) + 2 πn

y = arcsin (- cos (x) + c_{1}) + 2 πn, y = π + arcsin (cos (x) - c_{1}) + 2 πn

\frac{d y}{d x} = \frac{4 x}{3 y + 1}

x \frac{d y}{d x} - (1 - x^{2}) y = 0

y^{^{'}} = x y^{\frac{1}{2}}, y (0) = \frac{1}{16} x^{4}

e^{x} (\frac{d y}{d x}) = 1 + y^{2}

\frac{d y}{d x} = 4 x 36 - y^{2}

What is the solution for cos(y)dy=sin(x)dx ?
The solution for cos(y)dy=sin(x)dx is y=arcsin(-cos(x)+c_{1})+2pin,y=pi+arcsin(cos(x)-c_{1})+2pin