What is the solution for y^'=sin(y)*tan(y) ?

The solution for y^'=sin(y)*tan(y) is y=arccsc(-t-c_{1})+2pin,y=pi+arccsc(t+c_{1})+2pin

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y^'=sin(y)*tan(y)

y^{^{'}} = sin (y) \cdot tan (y)

y = arccsc (- t - c_{1}) + 2 πn, y = π + arccsc (t + c_{1}) + 2 πn

Solution steps

y^{'} (t) = sin (y) \cdot tan (y)

Solve separable ODE:

y = arccsc (- t - c_{1}) + 2 πn, y = π + arccsc (t + c_{1}) + 2 πn

y = arccsc (- t - c_{1}) + 2 πn, y = π + arccsc (t + c_{1}) + 2 πn

\frac{d y}{d x} = (\frac{x + 1}{y})

y^{^{'}} = 4 + 14 x + 12 y + 42 x y

P^{^{'}} = 0.2 P (1 - \frac{P}{2500})

\frac{d y}{d x} = 4 x e^{- y}

(t^{2} - 26 t + 133) \frac{d y}{d t} = y

What is the solution for y^'=sin(y)*tan(y) ?
The solution for y^'=sin(y)*tan(y) is y=arccsc(-t-c_{1})+2pin,y=pi+arccsc(t+c_{1})+2pin