What is the solution for (dy)/(dx)+by-a=0 ?

The solution for (dy)/(dx)+by-a=0 is y=-(e^{-bx-c_{1}b})/b+a/b

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(dy)/(dx)+by-a=0

\frac{d y}{d x} + b y - a = 0

y = - \frac{e ^{- b x - c_{1} b}}{b} + \frac{a}{b}

Solution steps

\frac{d y}{d x} + b y (x) - a = 0

Solve separable ODE:

y = - \frac{e ^{- b x - c_{1} b}}{b} + \frac{a}{b}

y = - \frac{e ^{- b x - c_{1} b}}{b} + \frac{a}{b}

d x + (\frac{y - 1}{x ^{2}})^{3} d y = 0

\frac{d x}{2 x} + \frac{d y}{2 y} = y d x + x d y

y^{^{'}} = 2 t y cos (t^{2})

\frac{d y}{d x} = \frac{x y}{y + 1}

y^{^{'}} sec (x) = 4 y^{2}, y (\frac{5 π}{2}) = \frac{1}{5}

What is the solution for (dy)/(dx)+by-a=0 ?
The solution for (dy)/(dx)+by-a=0 is y=-(e^{-bx-c_{1}b})/b+a/b