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Popular >

y^'=2tycos(t^2)

Solution

y^{^{'}} = 2 t y cos (t^{2})

Solution

y = e^{s i n (t^{2}) + c_{1}}

Solution steps

y^{'} (t) = 2 t y cos (t^{2})

Solve separable ODE:

y = e^{s i n (t^{2}) + c_{1}}

y = e^{s i n (t^{2}) + c_{1}}

Popular Examples

(dy)/(dx)=(xy)/(y+1)

\frac{d y}{d x} = \frac{x y}{y + 1}

y^'sec(x)=4y^2,y((5pi)/2)= 1/5

y^{^{'}} sec (x) = 4 y^{2}, y (\frac{5 π}{2}) = \frac{1}{5}

x^'=0.902+723.749*x

x^{^{'}} = 0.902 + 723.749 \cdot x

(2 x + 3) y^{^{'}} = y + 4

y^'=(-(3y^2+1)x)/(x^2+1),y(0)=1

y^{^{'}} = \frac{- ( 3 y ^{2} + 1 ) x}{x ^{2} + 1}, y (0) = 1

Frequently Asked Questions (FAQ)

What is the solution for y^'=2tycos(t^2) ?
The solution for y^'=2tycos(t^2) is y=e^{sin(t^2)+c_{1}}