What is the solution for x^'=0.902+723.749*x ?

The solution for x^'=0.902+723.749*x is x=(e^{723.74899…t+c_{1}})/(723.749)-(0.902)/(723.749)

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x^'=0.902+723.749*x

x^{^{'}} = 0.902 + 723.749 \cdot x

x = \frac{e ^{723.74899 \dots t + c_{1}}}{723.749} - \frac{0.902}{723.749}

Solution steps

x^{'} (t) = 0.902 + 723.749 \cdot x

Solve separable ODE:

x = \frac{e ^{723.74899 \dots t + c_{1}}}{723.749} - \frac{0.902}{723.749}

x = \frac{e ^{723.74899 \dots t + c_{1}}}{723.749} - \frac{0.902}{723.749}

(2 x + 3) y^{^{'}} = y + 4

y^{^{'}} = \frac{- ( 3 y ^{2} + 1 ) x}{x ^{2} + 1}, y (0) = 1

y^{^{'}} = \frac{240 - 6 y}{180}

\frac{d y}{d t} = t y^{2} + 2 y^{2}, y (0) = 1

sin (2 x) d x + cos (9 y) d y = 0

What is the solution for x^'=0.902+723.749*x ?
The solution for x^'=0.902+723.749*x is x=(e^{723.74899…t+c_{1}})/(723.749)-(0.902)/(723.749)