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Popular >

y^'+1/2 y= 5/2

Solution

y^{^{'}} + \frac{1}{2} y = \frac{5}{2}

Solution

y = - e^{\frac{- t - c _{1}}{2}} + 5

Solution steps

y^{'} (t) + \frac{1}{2} y = \frac{5}{2}

Solve separable ODE:

y = - e^{\frac{- t - c _{1}}{2}} + 5

y = - e^{\frac{- t - c _{1}}{2}} + 5

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Frequently Asked Questions (FAQ)

What is the solution for y^'+1/2 y= 5/2 ?
The solution for y^'+1/2 y= 5/2 is y=-e^{(-t-c_{1})/2}+5