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Popular >

yy^'-x=0

Solution

y y^{^{'}} - x = 0

Solution

y = x^{2} + c_{1}, y = - x^{2} + c_{1}

Solution steps

y y^{'} (x) - x = 0

Solve separable ODE:

y = x^{2} + c_{1}, y = - x^{2} + c_{1}

y = x^{2} + c_{1}, y = - x^{2} + c_{1}

Popular Examples

x*(y+2)*(dy)/(dx)=ln(x)+1

x \cdot (y + 2) \cdot \frac{d y}{d x} = ln (x) + 1

(dr)/(dt)=-4rt,r=r^0,t=0

\frac{d r}{d t} = - 4 r t, r = r^{0}, t = 0

y^'=(3+sin(t))y^2

y^{^{'}} = (3 + sin (t)) y^{2}

(dy)/(dt)=10-2y^2

\frac{d y}{d t} = 10 - 2 y^{2}

y^{^{'}} = - x^{2} \cdot (y)^{2}

Frequently Asked Questions (FAQ)

What is the solution for yy^'-x=0 ?
The solution for yy^'-x=0 is y=sqrt(x^2+c_{1)},y=-sqrt(x^2+c_{1)}