en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'=(3+sin(t))y^2

Solution

y^{^{'}} = (3 + sin (t)) y^{2}

Solution

y = - \frac{1}{3 t - cos ( t ) + c _{1}}

Solution steps

y^{'} (t) = (3 + sin (t)) y^{2}

Solve separable ODE:

y = - \frac{1}{3 t - cos ( t ) + c _{1}}

y = - \frac{1}{3 t - cos ( t ) + c _{1}}

Popular Examples

(dy)/(dt)=10-2y^2

\frac{d y}{d t} = 10 - 2 y^{2}

y^{^{'}} = - x^{2} \cdot (y)^{2}

(dy)/(dx)=(-0.7)/(cos(y)),y(0)= pi/3

\frac{d y}{d x} = \frac{- 0.7}{cos ( y )}, y (0) = \frac{π}{3}

dy(y+x^2y)=2xdx

d y (y + x^{2} y) = 2 x d x

y^'=xy^3(1+x^2)^{-1/2},y(0)=-1

y^{^{'}} = x y^{3} (1 + x^{2})^{- \frac{1}{2}}, y (0) = - 1

Frequently Asked Questions (FAQ)

What is the solution for y^'=(3+sin(t))y^2 ?
The solution for y^'=(3+sin(t))y^2 is y=-1/(3t-cos(t)+c_{1)}