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Popular >

y^'=-x^2*(y)^2

Solution

y^{^{'}} = - x^{2} \cdot (y)^{2}

Solution

y = - \frac{3}{- x ^{3} + c _{1}}

Solution steps

y^{'} (x) = - x^{2} \cdot (y)^{2}

Solve separable ODE:

y = - \frac{3}{- x ^{3} + c _{1}}

y = - \frac{3}{- x ^{3} + c _{1}}

Popular Examples

(dy)/(dx)=(-0.7)/(cos(y)),y(0)= pi/3

\frac{d y}{d x} = \frac{- 0.7}{cos ( y )}, y (0) = \frac{π}{3}

dy(y+x^2y)=2xdx

d y (y + x^{2} y) = 2 x d x

y^'=xy^3(1+x^2)^{-1/2},y(0)=-1

y^{^{'}} = x y^{3} (1 + x^{2})^{- \frac{1}{2}}, y (0) = - 1

(dy)/(dx)=(-0.7)/(cos(y)),y(0)= pi/2

\frac{d y}{d x} = \frac{- 0.7}{cos ( y )}, y (0) = \frac{π}{2}

(y-y^')/(x^2)=0

\frac{y - y ^{^{'}}}{x ^{2}} = 0

Frequently Asked Questions (FAQ)

What is the solution for y^'=-x^2*(y)^2 ?
The solution for y^'=-x^2*(y)^2 is y=-3/(-x^3+c_{1)}