What is the solution for (dy)/(dx)+9xy=4x,y(0)=5 ?

The solution for (dy)/(dx)+9xy=4x,y(0)=5 is y=(41e^{-(9x^2)/2})/(9)+4/9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)+9xy=4x,y(0)=5

\frac{d y}{d x} + 9 x y = 4 x, y (0) = 5

y = \frac{41 e ^{- \frac{9 x ^{2}}{2}}}{9} + \frac{4}{9}

Solution steps

\frac{d y}{d x} + 9 x y = 4 x

Solve separable ODE:

y = \frac{41 e ^{- \frac{9 x ^{2}}{2}}}{9} + \frac{4}{9}

y = \frac{41 e ^{- \frac{9 x ^{2}}{2}}}{9} + \frac{4}{9}

\frac{d y}{d x} y = (sin^{2} (π - x))

\frac{d P}{d t} = 0.0017 P (1 - \frac{P}{6200})

\frac{d y}{d x} + 15 x^{2} y = 2 x^{2}, y (0) = 3

\frac{d x}{d t} = 80 - \frac{x}{1000}, x = 5000, t = 0

\frac{d y}{d x} = \frac{y}{1 - x ^{2}}

What is the solution for (dy)/(dx)+9xy=4x,y(0)=5 ?
The solution for (dy)/(dx)+9xy=4x,y(0)=5 is y=(41e^{-(9x^2)/2})/(9)+4/9