What is the solution for (dy)/(dx)+15x^2y=2x^2,y(0)=3 ?

The solution for (dy)/(dx)+15x^2y=2x^2,y(0)=3 is y=(43e^{-5x^3})/(15)+2/15

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)+15x^2y=2x^2,y(0)=3

\frac{d y}{d x} + 15 x^{2} y = 2 x^{2}, y (0) = 3

y = \frac{43 e ^{- 5 x^{3}}}{15} + \frac{2}{15}

Solution steps

\frac{d y}{d x} + 15 x^{2} y = 2 x^{2}

Solve separable ODE:

y = \frac{43 e ^{- 5 x^{3}}}{15} + \frac{2}{15}

y = \frac{43 e ^{- 5 x^{3}}}{15} + \frac{2}{15}

\frac{d x}{d t} = 80 - \frac{x}{1000}, x = 5000, t = 0

\frac{d y}{d x} = \frac{y}{1 - x ^{2}}

y^{^{'}} = 16 y - 20

\frac{d y}{d x} = 8 - 15 y

\frac{d y}{d x} = \frac{2 x + 1}{2 y}, y (- 2) = - 1

What is the solution for (dy)/(dx)+15x^2y=2x^2,y(0)=3 ?
The solution for (dy)/(dx)+15x^2y=2x^2,y(0)=3 is y=(43e^{-5x^3})/(15)+2/15