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Popular >

y^'=16y-20

Solution

y^{^{'}} = 16 y - 20

Solution

y = \frac{e ^{16 t + c_{1}}}{4} + \frac{5}{4}

Solution steps

y^{'} (t) = 16 y - 20

Solve separable ODE:

y = \frac{e ^{16 t + c_{1}}}{4} + \frac{5}{4}

y = \frac{e ^{16 t + c_{1}}}{4} + \frac{5}{4}

Popular Examples

(dy)/(dx)=8-15y

\frac{d y}{d x} = 8 - 15 y

(dy)/(dx)=(2x+1)/(2y),y(-2)=-1

\frac{d y}{d x} = \frac{2 x + 1}{2 y}, y (- 2) = - 1

2 y = 3 - x y^{^{'}}

\frac{1}{y} d y = - \frac{1}{x} d x

e^yy^'=((ln(t))^2)/t ,y(1)=ln(10)

e^{y} y^{^{'}} = \frac{( ln ( t ) ) ^{2}}{t}, y (1) = ln (10)

Frequently Asked Questions (FAQ)

What is the solution for y^'=16y-20 ?
The solution for y^'=16y-20 is y=(e^{16t+c_{1}})/4+5/4