What is the solution for (dy)/(dx)y^2=ln(x) ?

The solution for (dy)/(dx)y^2=ln(x) is y=\sqrt[3]{3xln(x)-3x+c_{1}}

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(dy)/(dx)y^2=ln(x)

\frac{d y}{d x} y^{2} = ln (x)

Solution steps

\frac{d y}{d x} y^{2} = ln (x)

Solve separable ODE:

y^{^{'}} = 1 - 0.4 y

y^{^{'}} = \frac{8 x ^{3} + 1}{3 y ^{2}}

\frac{d y}{d x} = - \frac{0.9}{cos ( y )}, y (0) = \frac{π}{3}

y^{^{'}} = t (1 + \frac{y}{4}), y (1) = 2.4

\frac{d y}{d x} = \frac{5 x}{e ^{y}}

What is the solution for (dy)/(dx)y^2=ln(x) ?
The solution for (dy)/(dx)y^2=ln(x) is y=\sqrt[3]{3xln(x)-3x+c_{1}}