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Popular >

y^'-5y=10,y(0)=0

Solution

y^{^{'}} - 5 y = 10, y (0) = 0

Solution

y = 2 e^{5 t} - 2

Solution steps

y^{'} (t) - 5 y = 10

Solve separable ODE:

y = 2 e^{5 t} - 2

y = 2 e^{5 t} - 2

Popular Examples

f^{^{'}} (p) - f (p) = 0

((e^{3x}+3)e^y)dy-((e^y-4)e^{3x})dx=0

((e^{3 x} + 3) e^{y}) d y - ((e^{y} - 4) e^{3 x}) d x = 0

(dy)/(dx)y=(6x-4)^3

\frac{d y}{d x} y = (6 x - 4)^{3}

2= 1/10 y+(100*10^{-3})y^'

2 = \frac{1}{10} y + (100 \cdot 1 0^{- 3}) y^{^{'}}

(dy)/(dx)=x^3y^2-xy^2

\frac{d y}{d x} = x^{3} y^{2} - x y^{2}

Frequently Asked Questions (FAQ)

What is the solution for y^'-5y=10,y(0)=0 ?
The solution for y^'-5y=10,y(0)=0 is y=2e^{5t}-2