en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'-2y=10,y(0)=0

Solution

y^{^{'}} - 2 y = 10, y (0) = 0

Solution

y = 5 e^{2 t} - 5

Solution steps

y^{'} (t) - 2 y = 10

Solve separable ODE:

y = 5 e^{2 t} - 5

y = 5 e^{2 t} - 5

Popular Examples

y^2sec(4x)(dy)/(dx)=1,y(0)=0

y^{2} sec (4 x) \frac{d y}{d x} = 1, y (0) = 0

y^'sin(y)+xcos(y)+x=0

y^{^{'}} sin (y) + x cos (y) + x = 0

y^'=(x+xy)/(1+x^2)

y^{^{'}} = \frac{x + x y}{1 + x ^{2}}

(dy)/(dx)x^2+2x^2y+3xy=0

\frac{d y}{d x} x^{2} + 2 x^{2} y + 3 x y = 0

(dx)/(dt)=20-0.4x

\frac{d x}{d t} = 20 - 0.4 x

Frequently Asked Questions (FAQ)

What is the solution for y^'-2y=10,y(0)=0 ?
The solution for y^'-2y=10,y(0)=0 is y=5e^{2t}-5