What is the solution for (dy)/(dx)x^2+2x^2y+3xy=0 ?

The solution for (dy)/(dx)x^2+2x^2y+3xy=0 is y=(e^{-2x+c_{1}})/(x^3)

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(dy)/(dx)x^2+2x^2y+3xy=0

\frac{d y}{d x} x^{2} + 2 x^{2} y + 3 x y = 0

y = \frac{e ^{- 2 x + c_{1}}}{x ^{3}}

Solution steps

\frac{d y}{d x} x^{2} + 2 x^{2} y + 3 x y = 0

Solve separable ODE:

y = \frac{e ^{- 2 x + c_{1}}}{x ^{3}}

y = \frac{e ^{- 2 x + c_{1}}}{x ^{3}}

\frac{d x}{d t} = 20 - 0.4 x

(1 - y^{2}) d x = x y d y

\frac{1}{y} \frac{d y}{d x} = x^{- 1} + x^{2}

\frac{d y}{d x} = y^{2} + 1, y (0) = 0

\frac{d p}{d t} = 2 pt, p (1) = 6

What is the solution for (dy)/(dx)x^2+2x^2y+3xy=0 ?
The solution for (dy)/(dx)x^2+2x^2y+3xy=0 is y=(e^{-2x+c_{1}})/(x^3)