What is the solution for (dy)/(dt)=k(650-y),y(0)=300 ?

The solution for (dy)/(dt)=k(650-y),y(0)=300 is y=-350e^{-kt}+650

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(dy)/(dt)=k(650-y),y(0)=300

\frac{d y}{d t} = k (650 - y), y (0) = 300

y = - 350 e^{- k t} + 650

Solution steps

\frac{d y}{d t} = k (650 - y)

Solve separable ODE:

y = - 350 e^{- k t} + 650

y = - 350 e^{- k t} + 650

\frac{d y}{d x} = \frac{20 x y}{( ln ( y ) ) ^{6}}

f^{^{'}} (x) = f (x) (x)^{- 1} (x)

\frac{d y}{d x} = (\frac{y + 1}{x})

\frac{d y}{d x} = y (10000 - 50 x)

81 x^{2} + 2 y \cdot \frac{d y}{d x} = 0

What is the solution for (dy)/(dt)=k(650-y),y(0)=300 ?
The solution for (dy)/(dt)=k(650-y),y(0)=300 is y=-350e^{-kt}+650