What is the solution for (dy)/(dx)xy+2x+3x^2=4 ?

The solution for (dy)/(dx)xy+2x+3x^2=4 is y=sqrt(8ln(x)-4x-3x^2+c_{1)},y=-sqrt(8ln(x)-4x-3x^2+c_{1)}

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(dy)/(dx)xy+2x+3x^2=4

\frac{d y}{d x} x y + 2 x + 3 x^{2} = 4

y = 8 ln (x) - 4 x - 3 x^{2} + c_{1}, y = - 8 ln (x) - 4 x - 3 x^{2} + c_{1}

Solution steps

\frac{d y}{d x} x y + 2 x + 3 x^{2} = 4

Solve separable ODE:

y = 8 ln (x) - 4 x - 3 x^{2} + c_{1}, y = - 8 ln (x) - 4 x - 3 x^{2} + c_{1}

y = 8 ln (x) - 4 x - 3 x^{2} + c_{1}, y = - 8 ln (x) - 4 x - 3 x^{2} + c_{1}

y^{2} \frac{d y}{d x} + 2 x y^{3} = 6 x, y (0) = 1

\frac{d y}{d x} = 3.2 y^{\frac{2}{3}}, x (0) = 1, y (0) = 13

\frac{d}{d x} ((y) x) + 2 y = 0

3 y^{^{'}} - 4 y - 91 = 2 y^{^{'}}

3 (y^{2} + 1) d x + 2 x y d y = 0

What is the solution for (dy)/(dx)xy+2x+3x^2=4 ?
The solution for (dy)/(dx)xy+2x+3x^2=4 is y=sqrt(8ln(x)-4x-3x^2+c_{1)},y=-sqrt(8ln(x)-4x-3x^2+c_{1)}