What is the solution for (dy)/(dt)=(4t^2)/(3y) ?

The solution for (dy)/(dt)=(4t^2)/(3y) is y=(sqrt(c_{1)+8t^3})/3 ,y=-(sqrt(c_{1)+8t^3})/3

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(dy)/(dt)=(4t^2)/(3y)

\frac{d y}{d t} = \frac{4 t ^{2}}{3 y}

y = \frac{c _{1} + 8 t ^{3}}{3}, y = - \frac{c _{1} + 8 t ^{3}}{3}

Solution steps

\frac{d y}{d t} = \frac{4 t ^{2}}{3 y}

Solve separable ODE:

y = \frac{c _{1} + 8 t ^{3}}{3}, y = - \frac{c _{1} + 8 t ^{3}}{3}

y = \frac{c _{1} + 8 t ^{3}}{3}, y = - \frac{c _{1} + 8 t ^{3}}{3}

2 x y^{^{'}} = 1 - y^{2}

x^{^{'}} - 5 x = 25

\frac{d}{d θ} (r (θ)) = \frac{r ( θ ) ^{2}}{θ}, r (1) = 2

\frac{d y}{d t} + 7 y = 6, y (0) = 0

x f^{^{'}} (x) = (f (x))^{2}

What is the solution for (dy)/(dt)=(4t^2)/(3y) ?
The solution for (dy)/(dt)=(4t^2)/(3y) is y=(sqrt(c_{1)+8t^3})/3 ,y=-(sqrt(c_{1)+8t^3})/3