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Popular >

yx=-y^'

Solution

y x = - y^{^{'}}

Solution

y = e^{- \frac{x ^{2}}{2} + c_{1}}

Solution steps

y x = - y^{'} (x)

Solve separable ODE:

y = e^{- \frac{x ^{2}}{2} + c_{1}}

y = e^{- \frac{x ^{2}}{2} + c_{1}}

Popular Examples

(t^2-24t+119)((dy)/(dt))=y

(t^{2} - 24 t + 119) (\frac{d y}{d t}) = y

e^xcos(y)dx-e^xsin(y)dy=0

e^{x} cos (y) d x - e^{x} sin (y) d y = 0

y^{^{'}} - 3 y x = 2 x

(dy)/(dx)=(3x^2+4x-2)/(2(y-1))

\frac{d y}{d x} = \frac{3 x ^{2} + 4 x - 2}{2 ( y - 1 )}

y - y^{^{'}} + y = 0

Frequently Asked Questions (FAQ)

What is the solution for yx=-y^' ?
The solution for yx=-y^' is y=e^{-(x^2)/2+c_{1}}