What is the solution for 4y^{11}+y^'=0 ?

The solution for 4y^{11}+y^'=0 is y=\sqrt[10]{-1/(10(-4t+c_{1))}},y=-\sqrt[10]{-1/(10(-4t+c_{1))}}

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4y^{11}+y^'=0

4 y^{11} + y^{^{'}} = 0

Solution steps

4 y^{11} + y^{'} (t) = 0

Solve separable ODE:

\frac{d p}{d t} = t^{2} p - 7 p + t^{2} - 7

6 \frac{d y}{d x} + 5 x^{2} y = 97 x^{2}

\frac{d y}{d t} = y \cdot t^{3} - 1.5 \cdot y

y^{^{'}} = \frac{x}{2} - \frac{x}{2} y

\frac{d y}{d x} - \frac{( y ^{2} - y )}{sin ( x )} = 0

What is the solution for 4y^{11}+y^'=0 ?
The solution for 4y^{11}+y^'=0 is y=\sqrt[10]{-1/(10(-4t+c_{1))}},y=-\sqrt[10]{-1/(10(-4t+c_{1))}}