What is the solution for y+x(dy)/(dx)=2x^2y(dy)/(dx)+2xy^2 ?

The solution for y+x(dy)/(dx)=2x^2y(dy)/(dx)+2xy^2 is y=(c_{1})/x

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y+x(dy)/(dx)=2x^2y(dy)/(dx)+2xy^2

y + x \frac{d y}{d x} = 2 x^{2} y \frac{d y}{d x} + 2 x y^{2}

y = \frac{c _{1}}{x}

Solution steps

y + x \frac{d y}{d x} = 2 x^{2} y \frac{d y}{d x} + 2 x y^{2}

Solve separable ODE:

y = \frac{c _{1}}{x}

y = \frac{c _{1}}{x}

\frac{d y}{d t} = 3 - 0.04 y

\frac{x y + 3 x - y - 3}{x y - 2 x + 4 y - 8} = \frac{d y}{d x}

(t^{2} - 14 t + 45) \frac{d y}{d t} = y

\frac{d y}{d x} = y^{2} (7 - e^{x})

y^{^{'}} = 3 y - 7

What is the solution for y+x(dy)/(dx)=2x^2y(dy)/(dx)+2xy^2 ?
The solution for y+x(dy)/(dx)=2x^2y(dy)/(dx)+2xy^2 is y=(c_{1})/x