What is the solution for (dy)/(dx)y=(3-x^3) ?

The solution for (dy)/(dx)y=(3-x^3) is y=sqrt(6x-(x^4)/2+c_{1)},y=-sqrt(6x-(x^4)/2+c_{1)}

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(dy)/(dx)y=(3-x^3)

\frac{d y}{d x} y = (3 - x^{3})

y = 6 x - \frac{x ^{4}}{2} + c_{1}, y = - 6 x - \frac{x ^{4}}{2} + c_{1}

Solution steps

\frac{d y}{d x} y = (3 - x^{3})

Solve separable ODE:

y = 6 x - \frac{x ^{4}}{2} + c_{1}, y = - 6 x - \frac{x ^{4}}{2} + c_{1}

y = 6 x - \frac{x ^{4}}{2} + c_{1}, y = - 6 x - \frac{x ^{4}}{2} + c_{1}

\frac{d y}{d x} = e^{x + y} + e^{x - y}

y^{^{'}} - \frac{y}{( ln ( y ) ) ^{2}} = 0

(3 x^{2} + 2)^{3} \frac{d y}{d x} - x y^{2} = 0, y (0) = 2

\frac{d y}{d t} = 4 (1 - y)^{2}

y + x y^{^{'}} = 9

What is the solution for (dy)/(dx)y=(3-x^3) ?
The solution for (dy)/(dx)y=(3-x^3) is y=sqrt(6x-(x^4)/2+c_{1)},y=-sqrt(6x-(x^4)/2+c_{1)}