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Popular >

y^2y^'=-2xy,y(0)=2

Solution

y^{2} y^{^{'}} = - 2 x y, y (0) = 2

Solution

y = - 2 x^{2} + 4

Solution steps

y^{2} y^{'} (x) = - 2 x y

Solve separable ODE:

y = - 2 x^{2} + 4

y = - 2 x^{2} + 4

Popular Examples

(dy}{dx}=\frac{x-5)/y

\frac{d y}{d x} = \frac{x - 5}{y}

(dy)/(dx)=-3/4 x^4y^3

\frac{d y}{d x} = - \frac{3}{4} x^{4} y^{3}

y^2(3v+1)dv+y^2(-v^2)dy=0

y^{2} (3 v + 1) d v + y^{2} (- v^{2}) d y = 0

y^'=(x(x+1))/(4y^3)

y^{^{'}} = \frac{x ( x + 1 )}{4 y ^{3}}

5 y y^{^{'}} = x, y (5) = 2

Frequently Asked Questions (FAQ)

What is the solution for y^2y^'=-2xy,y(0)=2 ?
The solution for y^2y^'=-2xy,y(0)=2 is y=sqrt(-2x^2+4)