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Popular >

y^'-y=x+1

Solution

y^{^{'}} - y = x + 1

Solution

y = - x - 2 + c_{1} e^{x}

Solution steps

y^{'} (x) - y = x + 1

Solve linear ODE:

y = - x - 2 + c_{1} e^{x}

y = - x - 2 + c_{1} e^{x}

Popular Examples

inverse oflaplace (2s)/(s^2-8s+6)inverse laplace

\frac{2 s}{s ^{2} - 8 s + 6}

derivative of x^{(ln(2)/((1+ln(x)))})

\frac{d}{d x} (x^{\frac{l n ( 2 )}{( 1 + l n ( x ) )}})

tangent of f(x)=12(x-(1/x))^4,\at x=2 tangent of

f (x) = 12 (x - (\frac{1}{x}))^{4}, at x = 2

derivative of 5\sqrt[5]{x^3}

(dr)/(ds)=0.05r

\frac{d r}{d s} = 0.05 r

Frequently Asked Questions (FAQ)

What is the solution for y^'-y=x+1 ?
The solution for y^'-y=x+1 is y=-x-2+c_{1}e^x