What is the solution for (dN)/(dx)-0.3*N-32.4=0 ?

The solution for (dN)/(dx)-0.3*N-32.4=0 is N=(e^{0.3x+c_{1}})/(0.3)-(32.4)/(0.3)

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(dN)/(dx)-0.3*N-32.4=0

\frac{d N}{d x} - 0.3 \cdot N - 32.4 = 0

N = \frac{e ^{0.3 x + c_{1}}}{0.3} - \frac{32.4}{0.3}

Solution steps

\frac{d N}{d x} - 0.3 \cdot N - 32.4 = 0

Solve separable ODE:

N = \frac{e ^{0.3 x + c_{1}}}{0.3} - \frac{32.4}{0.3}

N = \frac{e ^{0.3 x + c_{1}}}{0.3} - \frac{32.4}{0.3}

\frac{d y}{d x} + 2 x y = x, y = \frac{1}{2} + \frac{1}{2} e^{- x^{2}}

\frac{d y}{d x} = \frac{x}{y}, y (0) = - 1

\frac{d P}{d t} = 8 Pt, P (1) = 6

y^{^{'}} = cos (t) \cdot y

y^{2} sec (2 x) \frac{d y}{d x} = 1, y (0) = 0

What is the solution for (dN)/(dx)-0.3*N-32.4=0 ?
The solution for (dN)/(dx)-0.3*N-32.4=0 is N=(e^{0.3x+c_{1}})/(0.3)-(32.4)/(0.3)