What is the solution for dy+sin(x)ydx-sin(x)dx=0 ?

The solution for dy+sin(x)ydx-sin(x)dx=0 is y=e^{cos(x)+c_{1}}+1

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dy+sin(x)ydx-sin(x)dx=0

d y + sin (x) y d x - sin (x) d x = 0

y = e^{c o s (x) + c_{1}} + 1

Solution steps

d y + sin (x) y d x - sin (x) d x = 0

Solve separable ODE:

y = e^{c o s (x) + c_{1}} + 1

y = e^{c o s (x) + c_{1}} + 1

\frac{( d y )}{( d t )} = 2 t cos^{(2)} (y)

(x^{2} + 4) \frac{d y}{d x} + x y = 2 x, y (0) = 3

\frac{d x}{d t} = x sin (t), x (0) = 3

x y^{^{'}} = \frac{3 y ^{3} + 12 y x ^{2}}{2 y ^{2} + 8 x ^{2}}

\frac{d y}{d x} = x y + 6 x + 3 y + 18

What is the solution for dy+sin(x)ydx-sin(x)dx=0 ?
The solution for dy+sin(x)ydx-sin(x)dx=0 is y=e^{cos(x)+c_{1}}+1