What is the solution for y^'-(7y)/(5160)=0.07 ?

The solution for y^'-(7y)/(5160)=0.07 is y=(e^{0.00135…t+c_{1}})/7-(361.2)/7

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y^'-(7y)/(5160)=0.07

y^{^{'}} - \frac{7 y}{5160} = 0.07

y = \frac{e ^{0.00135 \dots t + c_{1}}}{7} - \frac{361.2}{7}

Solution steps

y^{'} (t) - \frac{7 y}{5160} = 0.07

Solve separable ODE:

y = \frac{e ^{0.00135 \dots t + c_{1}}}{7} - \frac{361.2}{7}

y = \frac{e ^{0.00135 \dots t + c_{1}}}{7} - \frac{361.2}{7}

\frac{d y}{d x} = \frac{x cos ( x )}{y}, y (0) = - 2

e^{y} y^{^{'}} = \frac{( ( ln ( t ) ) ^{2} )}{t}

\frac{d y}{d u} + 3 u^{2} y = 5 u^{2}

\frac{d Q}{d t} = \frac{50 - Q}{10}

y^{2} (x d y - y d x) = 9 x^{2} (y d x - x d y)

What is the solution for y^'-(7y)/(5160)=0.07 ?
The solution for y^'-(7y)/(5160)=0.07 is y=(e^{0.00135…t+c_{1}})/7-(361.2)/7