What is the solution for 2x*y^'+y= 4/(y^2) ?

The solution for 2x*y^'+y= 4/(y^2) is y=\sqrt[3]{(-c_{1}+4x^{3/2})/(x^{3/2)}}

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2x*y^'+y= 4/(y^2)

2 x \cdot y^{^{'}} + y = \frac{4}{y ^{2}}

y = 3 \frac{- c _{1} + 4 x ^{\frac{3}{2}}}{x ^{\frac{3}{2}}}

Solution steps

2 x \cdot y^{'} (x) + y = \frac{4}{y ^{2}}

Solve separable ODE:

y = 3 \frac{- c _{1} + 4 x ^{\frac{3}{2}}}{x ^{\frac{3}{2}}}

y = 3 \frac{- c _{1} + 4 x ^{\frac{3}{2}}}{x ^{\frac{3}{2}}}

\frac{d y}{d t} + 0.9 t y = 4 t, y (0) = 6

y^{^{'}} = - \frac{2}{y}

y^{^{'}} = e^{3 y + 3 t}, y (0) = - 12

y^{^{'}} + \frac{1}{1 + x} y = \frac{2}{1 + x}

11 x - 8 y x^{2} + 1 \frac{d y}{d x} = 0, y (0) = 3

What is the solution for 2x*y^'+y= 4/(y^2) ?
The solution for 2x*y^'+y= 4/(y^2) is y=\sqrt[3]{(-c_{1}+4x^{3/2})/(x^{3/2)}}