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Popular >

y^'=(2x)/(y^2)

Solution

y^{^{'}} = \frac{2 x}{y ^{2}}

Solution

y = 3 3 x^{2} + c_{1}

Solution steps

y^{'} (x) = \frac{2 x}{y ^{2}}

Solve separable ODE:

y = 3 3 x^{2} + c_{1}

y = 3 3 x^{2} + c_{1}

Graph

Popular Examples

(dy)/(dx)=8y(-3-y)

\frac{d y}{d x} = 8 y (- 3 - y)

(dy)/(dx)=((1+2x)sqrt(y))

\frac{d y}{d x} = ((1 + 2 x) y)

e^{-x^2}(dy)/(dx)=x(y+2)^2,y(1)=2

e^{- x^{2}} \frac{d y}{d x} = x (y + 2)^{2}, y (1) = 2

y^'=yln(y)cot(x)

y^{^{'}} = y ln (y) cot (x)

(dy)/(dt)=-y/((4320/7))

\frac{d y}{d t} = - \frac{y}{( \frac{4320}{7} )}

Frequently Asked Questions (FAQ)

What is the solution for y^'=(2x)/(y^2) ?
The solution for y^'=(2x)/(y^2) is y=\sqrt[3]{3x^2+c_{1}}