What is the solution for (dy)/(dx)=3xy^2-2y^2 ?

The solution for (dy)/(dx)=3xy^2-2y^2 is y=-2/(3x^2-4x+c_{1)}

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(dy)/(dx)=3xy^2-2y^2

\frac{d y}{d x} = 3 x y^{2} - 2 y^{2}

y = - \frac{2}{3 x ^{2} - 4 x + c _{1}}

Solution steps

\frac{d y}{d x} = 3 x y^{2} - 2 y^{2}

Solve separable ODE:

y = - \frac{2}{3 x ^{2} - 4 x + c _{1}}

y = - \frac{2}{3 x ^{2} - 4 x + c _{1}}

\frac{d p}{d t} = \frac{p - 900}{2}

220 = (0.5) (x) + (15.5) \frac{d x}{d t} + (20)

x^{3} y^{^{'}} = y^{2} (x - 4)

\frac{d x}{d y} = y (4 x^{2} - 1)

\frac{d y}{d x} y = ln ((x^{5} + 7)^{2 π})

What is the solution for (dy)/(dx)=3xy^2-2y^2 ?
The solution for (dy)/(dx)=3xy^2-2y^2 is y=-2/(3x^2-4x+c_{1)}