What is the solution for y^'=((1-x))/y ,y(1)=1 ?

The solution for y^'=((1-x))/y ,y(1)=1 is y=sqrt(-x^2+2x)

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y^'=((1-x))/y ,y(1)=1

y^{^{'}} = \frac{( 1 - x )}{y}, y (1) = 1

y = - x^{2} + 2 x

Solution steps

y^{'} (x) = \frac{( 1 - x )}{y}

Solve separable ODE:

y = - x^{2} + 2 x

y = - x^{2} + 2 x

(x^{2} + 9) y^{^{'}} = x y

y^{^{'}} = \frac{y + 1}{x + 1}

\frac{d y}{d x} = \frac{4 y ^{\frac{3}{4}}}{x ^{2} + 1}, y (0) = 1

\frac{d y}{d t} = - \frac{1}{50} (y - 21)

\frac{d y}{d x} = \frac{- y}{3 x}

What is the solution for y^'=((1-x))/y ,y(1)=1 ?
The solution for y^'=((1-x))/y ,y(1)=1 is y=sqrt(-x^2+2x)