What is the solution for y^3(dy)/(dx)=-x^4 ?

The solution for y^3(dy)/(dx)=-x^4 is y=\sqrt[4]{-(4x^5)/5+c_{1}},y=-\sqrt[4]{-(4x^5)/5+c_{1}}

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y^3(dy)/(dx)=-x^4

y^{3} \frac{d y}{d x} = - x^{4}

y = 4 - \frac{4 x ^{5}}{5} + c_{1}, y = - 4 - \frac{4 x ^{5}}{5} + c_{1}

Solution steps

y^{3} \frac{d y}{d x} = - x^{4}

Solve separable ODE:

y = 4 - \frac{4 x ^{5}}{5} + c_{1}, y = - 4 - \frac{4 x ^{5}}{5} + c_{1}

y = 4 - \frac{4 x ^{5}}{5} + c_{1}, y = - 4 - \frac{4 x ^{5}}{5} + c_{1}

\frac{d y}{d x} = \frac{( 2 x + 1 ) ^{2}}{y}

\frac{d y}{d x} = y (x^{2} + 3)

\frac{d v}{d t} = 9.6138 - 8 v

\frac{d y}{d x} = - \frac{3 x + x y ^{2}}{2 y + x ^{2} y}

3 x^{2} (1 + y^{2}) d x - 2 y d y = 0

What is the solution for y^3(dy)/(dx)=-x^4 ?
The solution for y^3(dy)/(dx)=-x^4 is y=\sqrt[4]{-(4x^5)/5+c_{1}},y=-\sqrt[4]{-(4x^5)/5+c_{1}}